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Area of a Triangle Enclosed by a Straight Line and the x and y Axes 📂Geometry

Area of a Triangle Enclosed by a Straight Line and the x and y Axes

Overview

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Questions asking whether it’s possible to find the maximum or minimum value, or the tangent line often involve calculating the area of such triangles SS. Of course, finding the area of a triangle is not difficult, but it would be even better if one could remember a simple formula and solve it immediately.

Theorem

  • The yy intercept of the line y=mx+ny=mx+n is nn, and the xx intercept is nm-\frac { n }{ m }. The area of the triangle enclosed by this line and the xx axis, yy axis is as follows: S=n22m S = \left| \frac { n^{ 2 } }{ 2m } \right|
  • The yy intercept of the line ax+by+c=0ax+by+c=0 is cb-\frac { c }{ b }, and the xx intercept is ca-\frac { c }{ a }. The area of the triangle enclosed by this line and the xx axis, yy axis is as follows: S=c22ab S = \left| \frac { { c }^{ 2 } }{ 2ab } \right|