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Trigonometric Identities 📂Functions

Trigonometric Identities

Formula

The following identity holds for trigonometric functions.

cos2x+sin2x=11+tan2x=sec2x1+cot2x=csc2x \begin{align} \cos^{2} x + \sin^{2} x &= 1 \\ 1 + \tan^{2} x &= \sec^{2} x \\ 1 + \cot^{2} x &= \csc^{2} x \end{align}

Proof

(1)(1)

From the addition formula of trigonometric functions,

cos(xy)=cosxcosy+sinxsiny \cos (x - y) = \cos x \cos y + \sin x \sin y

Substituting y=xy= x,

cos0=cos2x+sin2x    cos2x+sin2x=1 \cos 0 = \cos^{2} x + \sin^{2} x \implies \cos^{2} x + \sin^{2} x = 1

(2)(2)

Dividing both sides of (1)(1) by cos2x\cos^{2}x,

cos2xcos2x+sin2xcos2x=1cos2x    1+tan2x=sec2x \dfrac{cos^{2}x}{\cos^{2}x} + \dfrac{\sin^{2}x}{\cos^{2}x} = \dfrac{1}{\cos^{2}x} \implies 1 + \tan^{2} x = \sec^{2} x

(3)(3)

Dividing both sides of (1)(1) by sin2x\sin^{2}x,

cos2xsin2x+sin2xsin2x=1sin2x    cot2x+1=csc2x \dfrac{\cos^{2}x}{\sin^{2}x} + \dfrac{\sin^{2}x}{\sin^{2}x} = \dfrac{1}{\sin^{2}x} \implies \cot^{2} x + 1 = \csc^{2} x