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Nilpotent Matrix 📂Matrix Algebra

Nilpotent Matrix

Definition1

n×nn \times n For a matrix AA, if there exists a positive integer kk that satisfies Ak=OA^{k} = O, then we call AA a nilpotent matrix. In this case, OO is the zero matrix of n×nn \times n.

Explanation

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“Nil” means ‘zero’ or ’none.’ “Potent” means ‘powerful,’ and is the root of the word “potential.” Therefore, the term “nilpotent” can be understood as ‘having the potential/power to become 00.’ In mathematics, ‘冪’ denotes exponentiation and ‘零’ denotes the number 00. Thus, the word “nilpotent” literally means ‘becoming zero upon exponentiation.’

Theorems

Proof

[1]

Shown by mathematical induction.

[2]

(    )(\implies) 2

Since AA is a square matrix, a Schur decomposition exists, and it can be represented as A=QTQA = Q T Q^{\ast} using some unitary matrix QQ and upper triangular matrix TT. Given that all eigenvalues of AA are 00, TT is an upper triangular matrix with all diagonal elements equal to 00. Since an upper triangular matrix is nilpotent, TT is nilpotent for some kNk \in \mathbb{N} such that Tk=OT^{k} = O. Consequently, AA is also nilpotent since Ak=QTkQ=OA^{k} = Q T^{k} Q^{*} = O holds for at least kk.

(    )(\impliedby) 3

Let us represent the zero vector as 0\mathbf{0}. kN:Ak=O \exists k \in \mathbb{N} : A^{k} = O For some eigenvalue λ\lambda of the nilpotent matrix AA and its corresponding eigenvector v\mathbf{v}, we can set it equal to λv=Av\lambda \mathbf{v} = A \mathbf{v}. By repeatedly multiplying both sides by AA, the following holds for kk. λkv=Akv=Ov=0 \lambda^{k} \mathbf{v} = A^{k} \mathbf{v} = O \mathbf{v} = \mathbf{0} Since this must hold for all eigenvectors v0\mathbf{v} \ne \mathbf{0}, all eigenvalues of AA must be λ=0\lambda = 0.

[3]

Proof omitted4.

See Also