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交代関数 📂関数

交代関数

定義

集合XXが与えられたとする。以下を満たす関数を交代関数alternating functionと呼ぶ。

ϕ:X×X××XnRϕ(x1,,xi,xi+1,,xn)=ϕ(x1,,xi+1,xi,,xn) \phi : \overbrace{X \times X \times \cdots \times X}^{n} \to \mathbb{R} \\ \phi (x_{1}, \dots, x_{i}, x_{i+1}, \dots, x_{n}) = - \phi (x_{1}, \dots, x_{i+1}, x_{i}, \dots, x_{n})

説明

隣り合う二つの変数の位置を変えるときに関数の符号が変わる関数だ。もちろん、定義により隣り合っていない二つの変数に対しても成り立つことを示すことができる。

変数に重複する要素が一つでもあれば、関数の値は00である。

性質

ϕ(x1,,xi,,xi+k,,xn)=ϕ(x1,,xi+k,,xi,,xn) \begin{equation} \phi (x_{1}, \dots, x_{i}, \dots, x_{i+k}, \dots, x_{n}) = - \phi (x_{1}, \dots, x_{i+k}, \dots, x_{i}, \dots, x_{n}) \end{equation}

ϕ\phiが交代関数であるための必要十分条件は以下の通りである。

ϕ(x1,,xi,xi,,xn)=0 \begin{equation} \phi (x_{1}, \dots, x_{i}, x_{i}, \dots, x_{n}) = 0 \end{equation}

証明

証明 (1)

ϕ(x1,,xi,,xi+k1,xi+k,,xn)= ϕ(x1,,xi,,xi+k,xi+k1,,xn)= (1)2ϕ(x1,,xi,,xi+k,xi+k2,xi+k1,,xn)= (1)kϕ(x1,,xi+k,xi,,xi+k2,xi+k1,,xn)= (1)k+1ϕ(x1,,xi+k,xi+1,xi,,xi+k2,xi+k1,,xn)= (1)k+(k1)ϕ(x1,,xi+k,,xi+k1,xi,,xn)= ϕ(x1,,xi+k,,xi+k1,xi,,xn) \begin{align*} & \phi (x_{1}, \dots, x_{i}, \dots, x_{i+k-1}, x_{i+k}, \dots, x_{n}) \\ =&\ - \phi (x_{1}, \dots, x_{i}, \dots, x_{i+k}, x_{i+k-1}, \dots, x_{n}) \\ =&\ (-1)^{2} \phi (x_{1}, \dots, x_{i}, \dots, x_{i+k}, x_{i+k-2}, x_{i+k-1}, \dots, x_{n}) \\ \vdots& \\ =&\ (-1)^{k} \phi (x_{1}, \dots, x_{i+k}, x_{i}, \dots, x_{i+k-2}, x_{i+k-1}, \dots, x_{n}) \\ =&\ (-1)^{k+1} \phi (x_{1}, \dots, x_{i+k}, x_{i+1} ,x_{i}, \dots, x_{i+k-2}, x_{i+k-1}, \dots, x_{n}) \\ \vdots& \\ =&\ (-1)^{k+(k-1)} \phi (x_{1}, \dots, x_{i+k}, \dots, x_{i+k-1}, x_{i}, \dots, x_{n}) \\ =&\ - \phi (x_{1}, \dots, x_{i+k}, \dots, x_{i+k-1}, x_{i}, \dots, x_{n}) \end{align*}

証明 (2)

ϕ(x1,,xi,xi,,xn)= ϕ(x1,,xi,xi,,xn)    2ϕ(x1,,xi,xi,,xn)= 0    ϕ(x1,,xi,xi,,xn)= 0 \begin{align*} && \phi (x_{1}, \dots, x_{i}, x_{i}, \dots, x_{n}) =&\ - \phi (x_{1}, \dots, x_{i}, x_{i}, \dots, x_{n}) \\ \iff && 2\phi (x_{1}, \dots, x_{i}, x_{i}, \dots, x_{n}) =&\ 0 \\ \iff && \phi (x_{1}, \dots, x_{i}, x_{i}, \dots, x_{n}) =&\ 0 \end{align*}