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Galois Theory 📂Abstract Algebra

Galois Theory

Theorem1

Let $K$ be a finite normal extension field of $F$, and let $F \le E \le K$. Denote by $\lambda (E)$ the subgroup of $G ( K / F )$ that leaves $E$ fixed. Then the map $\lambda$ is an isomorphism mapping every $E$ between $F$ and $K$ to every subgroup of $G ( K / F )$. $\lambda$ has the following properties.

  1. $\lambda ( E ) = G ( K / E )$
  2. $E = K_{ G ( K / E ) } = K_{ \lambda (E) }$
  3. For $H \le G ( K / F )$, $\lambda ( K_{H} ) = H$
  4. $[K : E] = | \lambda (E) |$ and $[ E : F ] = \left( G ( K / F ) : \lambda (E) \right)$
  5. $E$ is a normal extension field of $F$ $\iff$ $\lambda (E)$ is a normal subgroup of $G (K / F)$.
  6. If $\lambda (E)$ is a normal subgroup of $G ( K / F )$, then $G (E / F) \simeq G ( K / F ) / G ( K / E )$

  • $[ E : F ]$ means the degree.
  • $G(E / F)$ means the group of $E$ over $F$.
  • $\left( G ( K / F ) : \lambda (E) \right)$ means the index in group theory.
  • $K_{ \lambda (E) }$ is the set consisting only of the elements of $K$ fixed by $\lambda (E)$.

  1. Fraleigh. (2003). A first course in abstract algebra(7th Edition): p451. ↩︎