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Limit of Transition Probabilities 📂Probability Theory

Limit of Transition Probabilities

Definition

When the current state is ii, after going through kk steps to reach jj, the transition probability is denoted as pij(k)p_{ij}^{(k)}. The transition probability after an infinite number of steps is represented as follows: πj:=limnpij(n) \pi_{j}:= \lim_{n \to \infty} p_{ij}^{ ( n ) }

Description

Whether it’s statistics or applied mathematics, the main interest usually lies in predicting the future. What’s intriguing in the theory of stochastic processes is not just what happens next, but what happens in the distant future. And this representation often uses infinity.

As expressed by πj=iπipij\displaystyle \pi_{j} = \sum_{i} \pi_{i} p_{ij} in the definition, when represented as a matrix, for π:=[π1πk]\pi:= \begin{bmatrix} \pi_{1} & \cdots & \pi_{k} \end{bmatrix} and P:=[p1jp1jpnjpnj]P:= \begin{bmatrix} p_{1j} & \cdots & p_{1j} \\ \vdots & \ddots & \vdots \\ p_{nj} & \cdots & p_{nj} \end{bmatrix}, it can be presented as π=πP\pi = \pi P. Taking the transpose on both sides yields πT=PTπT\pi^{T} = P^{T} \pi^{T}.

To summarize, it becomes a simple problem of finding x:=πT=[π1πn]\mathbf{x} : = \pi^{T} = \begin{bmatrix} \pi_{1} \\ \vdots \\ \pi_{n} \end{bmatrix} that satisfies (PTI)x=0\left( P^{T} - I \right) \mathbf{x} = 0. If a limit exists, the problem is usually solved in this manner.

Example

Let’s calculate the limit for the following stochastic process.

20190122\_111128.png

The transition matrix can be represented as P:=[3/41/401/201/2001]P:= \begin{bmatrix} 3/4 & 1/4 & 0 \\ 1/2 & 0 & 1/2 \\ 0 & 0 & 1 \end{bmatrix}, and we need to solve (PTI)[πAπBπC]=0\left( P^{T} - I \right) \begin{bmatrix} \pi_{A} \\ \pi_{B} \\ \pi_{C} \end{bmatrix} = \mathbb{0}.

Since (PTI)=[1/41/201/41001/20]\left( P^{T} - I \right) = \begin{bmatrix} -1/4 & 1/2 & 0 \\ 1/4 & -1 & 0 \\ 0 & 1/2 & 0 \end{bmatrix}, we obtain the system of equations {1/4πA+1/2πB=01/4πAπB=0πB=0\begin{cases} - 1/4 \pi_{A} + 1/2 \pi_{B} = 0 \\ 1/4 \pi_{A} - \pi_{B} = 0 \\ \pi_{B} = 0 \end{cases}.

Solving the system of equations gives us πA=πB=0\pi_{A} = \pi_{B} = 0, and since πA+πB+πC=1\pi_{A} + \pi_{B} + \pi_{C} = 1, we also get up to πC=1\pi_{C} = 1.

This result is not significantly different from intuition, mathematically showing that if the process is repeated infinitely, it will eventually end at C.