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The Fundamental Theorem of Algebra Expressed in Terms of Abstract Algebra 📂Abstract Algebra

The Fundamental Theorem of Algebra Expressed in Terms of Abstract Algebra

Definition 1

Let EE be an extension field of field FF.

  1. If all polynomials have zeros in FF, then FF is said to be Algebraically Closed.
  2. FE:={αEα is algebraic over F}\overline{ F_{E}} : = \left\{ \alpha \in E \mid \alpha \text{ is algebraic over } F \right\} is called the Algebraic Closure of FF in EE.

Theorem

  • [1]: If FF is algebraically closed,     \iff then every f(x)F[x]f(x) \in F [ x ] is factored into terms of degree 11 in F[x]F [ x ].
  • [2]: There does not exist an algebraic extension field EE satisfying FEF \lneq E over the algebraically closed field FF.
  • [3]: The set of algebraic numbers forms a field.
  • [4]: FE\overline{ F_{E}} is a subfield of EE.
  • [5]: Every field has an algebraic closure.

  • Naturally, by polynomial here, we refer to polynomials other than the constant function.

Explanation

F\overline{F} is the set of elements we can algebraically obtain by expanding to EE while covering FF and taking up all the sets that we can get, up to the elements that are attainable algebraically. If you’re somewhat familiar with topology, you can think of it as analogous to obtaining a closed set F=Ff\overline{F} = F \cup f ' by combining FF with a target set ff '.

Through these expressions and theorems, the Fundamental Theorem of Algebra can be described as follows.

The field of complex numbers C\mathbb{C} is algebraically closed.

To unpack this, theorem [1] implies that polynomials with complex coefficients are factored into terms of degree 11 in C[x]\mathbb{C} [ x ], thus having exactly as many zeros as the degree of the highest term, including multiplicity. This is equivalent to the Fundamental Theorem of Algebra as we originally knew it.

Moreover, theorem [2] guarantees that there is no algebraic extension field which has C\mathbb{C} as a proper subset. This means there is no need to consider any field larger than C\mathbb{C}, effectively making C\mathbb{C} the largest field we deal with, a notion that is perfectly acceptable. This fact justifies studying the scalar field as the field of complex numbers in functional analysis and vector spaces, among others.

Proof

Proved with complex analysis.


  1. Fraleigh. (2003). A first course in abstract algebra(7th Edition): p286~287. ↩︎