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Urysohn's Lemma and Tietze Extension Theorem 📂Topology

Urysohn's Lemma and Tietze Extension Theorem

Theorem

Urysohn’s Lemma1

If $X$ is a normal space, then for all closed sets $A, B \subset X$ with $A \cap B = \emptyset$, there exists a continuous function $f:X \to [0,1]$ satisfying $f(A) = \left\{ 0 \right\}$ and $f(B) = \left\{ 1 \right\}$.

Tietze Extension Theorem2

For a closed set $C$ in a normal space $X$, if $f : C \to \mathbb{R}$ is continuous, then there exists a continuous function $F : X \to \mathbb{R}$ satisfying $F |_{C} = f$.

Explanation

Urysohn’s lemma is invoked in all sorts of fields that use topology, and fittingly, its very statement looks quintessentially topological.

The Tietze extension theorem is a theoretical foundation used so frequently in real function theory (probability theory) and the like that it is not even called a theorem separately.

However, since normality is a required condition, these theorems are not so easy to apply as they are. Perhaps for this reason, a great deal of effort is devoted in general topology to showing the normality of a space.

The relationships among spaces with separation properties can be diagrammed as follows.

20180813\_144524.png

That a space is a normal space essentially means it has almost all of the separation properties. Even if there were bizarre spaces like $T_{1.5}$ or $T_{3.5}$, as long as this kind of notation is being used, $T_{4}$ has their properties.


  1. Munkres. (2000). Topology(2nd Edition): p207. ↩︎

  2. Munkres. (2000). Topology(2nd Edition): p219. ↩︎