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Cyclic groups in Abstract Algebra 📂Abstract Algebra

Cyclic groups in Abstract Algebra

Definition 1

An element aa of a group GG is termed a cyclic group if there exists an integer nZn \in \mathbb{Z} such that for any xGx \in G, x=anx = a^{n} holds. It is denoted as a\braket{a}. The element aa is called the generator.

Explanation

Simply put, a cyclic group is one where every element can be expressed as a power of the generator. Since all elements are represented by repeated exponentiation, the term ‘cyclic’ is aptly fitting.

Though not immediately evident from the definition, every cyclic group is an Abelian group, and the generator is not necessarily unique. Theorem [1] illustrates this.

Furthermore, the definition does not necessitate that a cyclic group be a finite group. It is essential to note that nn exists as an integer rather than a natural number, indicating that even adding the inverse of the generator is permissible. Theorem [2] serves as an example of this.

Rotation

Let R2π/nR_{2\pi/n} be the rotation by an angle of 2π/n2\pi/n in the counterclockwise direction. Then, this becomes the generator of a rotation group completing a full circle in nn iterations.

R2π/n={R0,R2π/n,R4π/n,,R(n1)π/n} \braket{R_{2\pi/n}} = \left\{ R_{0}, R_{2\pi/n}, R_{4\pi/n}, \dots, R_{(n-1)\pi/n} \right\}

This is also referred to as a cyclic rotation group.

Theorems

  • [1]: The generator of Z4={0,1,2,3}\mathbb{Z}_{4} = \left\{ 0,1,2,3 \right\} is not unique.
  • [2]: Z\mathbb{Z} is a cyclic group.

Proofs

[1]

Although all elements can be represented by 11, they can also be represented by 33 since 31(mod4)3 \equiv -1 \pmod{4}.

Thus, <1>=<3>=Z4\left< 1 \right> = \left< 3 \right> = \mathbb{Z}_{4}, and it indicates that the generator is not required to be unique.

[2]

Every element of <Z,+>\left< \mathbb{Z} , + \right> can be expressed as 1n=(1)(n)=n1 \cdot n = (-1) \cdot (-n) = n, hence Z=<1>=<1>\mathbb{Z} = \left< 1 \right> = \left< -1 \right>.


  1. Fraleigh. (2003). A first course in abstract algebra(7th Edition): p59. ↩︎