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What is the Dot Product in Three-Dimensional Space? 📂Mathematical Physics

What is the Dot Product in Three-Dimensional Space?

Definition

The inner product of two 3-dimensional vectors A=(Ax,Ay,Az)\mathbf{A} = (A_{x}, A_{y}, A_{z}) and B=(Bx,By,Bz)\mathbf{B} = (B_{x}, B_{y}, B_{z}) is defined as follows.

AB:=AxBx+AyBy+AzBz \mathbf{A} \cdot \mathbf{B} := A_{x}B_{x} + A_{y}B_{y} + A_{z}B_{z}

Description

In fact, the above definition specifically refers to the dot product. The term inner product is a translation of inner product, which is often used to refer to a more general concept. However, in high school or physics classes, it is commonly just referred to as the inner product. Because the result of the calculation is a scalar (a constant), it is also called the scalar product.

Notation

Each component’s subscript is commonly notated with numbers as follows with the \sum symbol.

AB=A1B1+A2B2+A3B3=i=13AiBi=δijAiBj \mathbf{A} \cdot \mathbf{B} = A_{1}B_{1} + A_{2}B_{2} + A_{3}B_{3} = \sum_{i=1}^{3} A_{i}B_{i} = \delta_{ij}A_{i}B_{j}

Here, δij\delta_{ij} refers to the Kronecker delta.

Properties

  • Let A=Ax2+Ay2+Az2\left| \mathbf{A} \right| = \sqrt{A_{x}^{2} + A_{y}^{2} + A_{z}^{2}} be the magnitude of vector A\mathbf{A}, and let θ\theta be the angle between vectors A\mathbf{A} and B\mathbf{B}. Then the following holds: AB=ABcosθ \mathbf{A} \cdot \mathbf{B} = \left| \mathbf{A} \right| \left| \mathbf{B} \right| \cos\theta

    • For two vectors A\mathbf{A} and B\mathbf{B} that are perpendicular to each other, AB=0 \mathbf{A} \cdot \mathbf{B} = 0

    • Magnitude of a vector: A=AA\left| \mathbf{A} \right| = \sqrt{\mathbf{A} \cdot \mathbf{A}}

  • Commutative law: AB=BA\mathbf{A} \cdot \mathbf{B} = \mathbf{B} \cdot \mathbf{A}

  • Distributive law over addition: A(B+C)=AB+AC\mathbf{A} \cdot (\mathbf{B} + \mathbf{C}) = \mathbf{A} \cdot \mathbf{B} + \mathbf{A} \cdot \mathbf{C}

See also