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Lie Brackets of Vector Fields 📂Geometry

Lie Brackets of Vector Fields

Definition1

On two differentiable vector fields X,YX, Y on a differentiable manifold MM, [X,Y][X, Y] is defined as follows, and is called the (Lie-)bracket or Lie algebra.

[X,Y]:=XYYX \begin{equation} [X, Y] := XY - YX \end{equation}

Explanation

Vector field X,YX, Y can be seen as an operator acting on D(M)\mathcal{D}(M), and XYXY although not a vector field, [X,Y]=XYYX[X, Y] = XY - YX becomes a vector field.

(1)(1) satisfying such equation is generally called a commutator.

The following theorem states that (a), (b), (c) are generally satisfied properties not only for Lie-brackets but also for commutators. Especially, (c) is known as the Jacobi identity.

Theorem

Let X,Y,ZX, Y, Z be a differentiable vector field on MM. Let a,ba, b be a real number and f,gf, g be a differentiable function on MM. Then, the following holds:

(a) [X,Y]=[Y,X][X, Y] = -[Y, X]

(b) [aX+bY,Z]=a[X,Y]+b[Y,Z][aX + bY, Z] = a[X, Y] + b[Y, Z]

(c) [[X,Y],Z]+[[Y,Z],X]+[[Z,X],Y]=0[ [X, Y], Z] + [ [Y, Z], X] + [ [Z, X], Y] = 0

(d) [fX,gY]=fg[X,Y]+fX(g)YgY(f)X[fX, gY] = fg[X, Y] + fX(g)Y - gY(f)X

Proof

(d)

Since the differentiation of a product X(gY)=X(g)Y+gXYX(gY) = X(g)Y + gXY holds,

[fX,gY]=fX(gY)gY(fX)=(fX(g)Y+fgXY)(gY(f)XgfYX)=fgXYfgYX+fX(g)Y+gY(f)X=fg(XYYX)+fX(g)Y+gY(f)X=fg[X,Y]+fX(g)Y+gY(f)X \begin{align*} [fX, gY] &= fX(gY) - gY(fX) \\ &= \left( fX(g)Y + fgXY \right) - \left( gY(f)X - gfYX \right) \\ &= fgXY - fgYX + fX(g)Y + gY(f)X\\ &= fg(XY - YX) + fX(g)Y + gY(f)X\\ &= fg[X, Y] + fX(g)Y + gY(f)X \end{align*}


  1. Manfredo P. Do Carmo, Riemannian Geometry (Eng Edition, 1992), p27-28 ↩︎