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Positive Gaussian Curvature Surfaces of Revolution 📂Geometry

Positive Gaussian Curvature Surfaces of Revolution

Overview1

The surface of revolution created by the unit speed curve α(s)=(r(s),z(s))\boldsymbol{\alpha}(s) = \left( r(s), z(s) \right) is called MM.

M={(r(s)cosθ,r(s)sinθ,z(s)):0θ2π,s(s0,s1)} M = \left\{ \left( r(s)\cos\theta, r(s)\sin\theta, z(s) \right) : 0 \le \theta \le 2\pi, s \in (s_{0}, s_{1}) \right\}

The coordinate patch mapping x\mathbf{x} of MM is as follows.

x(s,θ)=(r(s)cosθ,r(s)sinθ,z(s)) \mathbf{x}(s, \theta) = \left( r(s)\cos\theta, r(s)\sin\theta, z(s) \right)

At this time, the Gaussian curvature of this surface of revolution is as follows.

K=rr K = -\dfrac{r^{\prime \prime}}{r}

Describes the surface of revolution with the Gaussian curvature being K=rr=a2K = -\dfrac{r^{\prime \prime}}{r} = a^{2} positive.

Description

Based on the above assumptions, we obtain r+a2r=0r^{\prime \prime} + a^{2}r = 0. Since this is a second-order ordinary differential equation, the solution is as follows.

r(s)=a1cos(as)+a2sin(as)=Acos(as+b) r(s) = a_{1}\cos(as) + a_{2}\sin(as) = A\cos(as + b)

Let’s denote this as b=0b=0. Then, assuming that there was r>0r>0, A>0A > 0, and therefore, s<π/2a\left| s \right| \lt \pi/2a. Also, since z=±1(r)2z^{\prime} = \pm\sqrt{1 - (r^{\prime})^{2}}, the following theorem is obtained.


Theorem

Let’s call MM a surface of revolution created by the unit speed curve α(s)\boldsymbol{\alpha}(s), and a constant K=a2K = a^{2} with positive Gaussian curvature. Then, α(s)=(r(s),z(s))\boldsymbol{\alpha}(s) = \left( r(s), z(s) \right) is given as follows.

r(s)=Acos(as),s<π/2az(s)=±0s1a2A2sin2(at)dt+C \begin{align} r(s) &= A\cos (as),\quad \left| s \right| \lt \pi/2a \nonumber \\ z(s) &= \pm \int_{0}^{s} \sqrt{1 - a^{2}A^{2} \sin^{2}(at)}dt + C \end{align}

Here, A>0,CA > 0, C is a constant.


If A1aA \ne \dfrac{1}{a}, the given integral (1)(1) does not appear as an elementary integral, which is called an elliptic integral.

If A=1aA = \dfrac{1}{a}, it’s simply z(s)=±0scos(at)dt+C=±1asin(as)+Cz(s) = \pm {\displaystyle \int}_{0}^{s} \cos(at)dt + C = \pm\frac{1}{a}\sin (as) + C. Therefore, since r2+z2=1a2r^{2} + z^{2} = \frac{1}{a^{2}}, the revolution surface MM is a sphere.

The shape of the surface of revolution depending on the value of AA is as follows:

slide29.png

Also, since r=Acos(as)r = A\cos(as), the matrix of metric coefficients is:

[gij]=[100A2cos2(as)] \begin{bmatrix} g_{ij} \end{bmatrix} = \begin{bmatrix} 1 & 0 \\ 0 & A^{2} \cos^{2}(as) \end{bmatrix}


  1. Richard S. Millman and George D. Parker, Elements of Differential Geometry (1977), p154 ↩︎