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Bartlett's Identity 📂Mathematical Statistics

Bartlett's Identity

Theorem

Regular Conditions:

  • (R0): The probability density function ff is injective with respect to θ\theta. Mathematically, it satisfies the following. θθ    f(xk;θ)f(xk;θ) \theta \ne \theta ' \implies f \left( x_{k} ; \theta \right) \ne f \left( x_{k} ; \theta ' \right)
  • (R1): The probability density function ff has the same support for all θ\theta.
  • (R2): The true value θ0\theta_{0} is an interior point of Ω\Omega.
  • (R3): The probability density function ff is twice differentiable with respect to θ\theta.
  • (R4): The integral f(x;θ)dx\int f (x; \theta) dx is twice differentiable with respect to θ\theta, across the integration sign.

Let us assume Regular Conditions (R0)~(R4) are satisfied.

  • [1] First identity: E[logf(X;θ)θ]=0 E \left[ {{ \partial \log f ( X ; \theta ) } \over { \partial \theta }} \right] = 0
  • [2] Second identity: E[2logf(X;θ)θ2]+Var(logf(X;θ)θ)=0 E \left[ {{ \partial^{2} \log f ( X ; \theta ) } \over { \partial \theta^{2} }} \right] + \operatorname{Var} \left( {{ \partial \log f ( X ; \theta ) } \over { \partial \theta }} \right) = 0

Derivation

Direct deduction using regular conditions.