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Test Functions and Test Function Space 📂Distribution Theory

Test Functions and Test Function Space

Definition1

Let an open set ΩRn\Omega \subset \mathbb{R}^{n} and a function ϕ:ΩC\phi : \Omega \to \mathbb{C} be given. If ϕ\phi is infinitely differentiable, and all its derivatives are continuous and have a compact support, it is called a test function. The function space of test functions is denoted by Cc(Ω)C_{c}^{\infty}(\Omega) or simply as D(Ω)\mathcal{D}(\Omega).

Explanation

It is also called a test function or testing function. The reason ϕ\phi is named a test function is not that we want to deal with ϕ\phi itself, but because we intend to define some other function and study its properties using ϕ\phi. Specifically, test functions are used to rigorously define functions with mathematical ambiguities such as the Dirac delta function. An example of a test function is a mollifier.

Theorem2

If ϕ\phi is a test function, then its derivative is also a test function.

ϕD(Ω)    ϕxiD(Ω)(i=1,,n) \phi \in \mathcal{D}(\Omega) \implies \frac{ \partial \phi}{ \partial x_{i}} \in \mathcal{D}(\Omega) (i=1,\cdots,n)

In this case, x=(x1,,xn)Rnx=(x_{1},\cdots,x_{n})\in \mathbb{R}^{n}.

Proof

It is trivial that ϕxiC\dfrac{ \partial \phi}{ \partial x_{i}} \in C^{\infty} by the definition of the test function. Let’s assume x0suppϕx_{0} \notin \mathrm{supp} \phi. Then x0(suppϕ)cx_{0} \in \left( \mathrm{supp} \phi \right)^{c}, and since the support is a closed set, (suppϕ)c(\mathrm{supp} \phi)^{c} is open. Therefore, there exists some neighborhood Nx0N_{x_{0}} that contains x0x_{0}, according to the definition of an open set. Also, by the definition of support, ϕ=0\phi=0 on Nx0N_{x_{0}}, and naturally ϕxi=0\dfrac{ \partial \phi}{ \partial x_{i}}=0. This implies x0suppϕxix_{0} \notin \mathrm{supp} \dfrac{ \partial \phi}{ \partial x_{i}}. Hence, the following holds:

suppϕxisuppϕ \mathrm{supp} \frac{ \partial \phi}{ \partial x_{i} } \subset \mathrm{supp} \phi

Since a closed subset of a compact set is compact, suppϕxi\mathrm{supp} \dfrac{ \partial \phi}{ \partial x_{i}} is compact.

Corollary

Let us assume ϕ,ϕ1,ϕ2D(Rn)\phi,\phi_{1},\phi_{2} \in \mathcal{D}(\mathbb{R}^{n}), x0Rnx_{0}\in \mathbb{R}^{n}, aR{0}a \in \mathbb{R}\setminus \left\{ 0 \right\}, ψC(Rn)\psi \in C^{\infty}(\mathbb{R}^{n}). Then the following holds:

  • (a) ϕ(xx0)\phi (x-x_{0}), ϕ(x)\phi (-x), ϕ(ax)D(Rn)\phi (ax)\in \mathcal{D}(\mathbb{R}^{n})

  • (b) ψϕD(Rn)\psi \phi \in \mathcal{D}(\mathbb{R}^{n})

  • (c) ϕ1ϕ2D\phi_{1} * \phi_{2} \in \mathcal{D}


The proof is omitted as it is obvious.


  1. Robert A. Adams and John J. F. Foutnier, Sobolev Space (2nd Edition, 2003), p19-20 ↩︎

  2. Daniel Eceizabarrena perez, Distribution Theory and Fundamental Solutions of Differential Operators (2015), p1-3 ↩︎