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Shaking Hands Dilemma Proof 📂Graph Theory

Shaking Hands Dilemma Proof

Theorem 1

In any directed graph, the sum of the in-degrees and the sum of the out-degrees are equal.

Explanation

The handshake dilemma can be considered the handshake lemma for directed graphs.

Proof

In a directed graph, the sum of the out-degrees is equal to the number of arcs. Since an arc comes out from one vertex and enters another, the sum of the out-degrees and in-degrees are equal.


  1. Wilson. (1970). Introduction to Graph Theory: p105. ↩︎