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Notation for Nonlinear First-Order Partial Differential Equations 📂Partial Differential Equations

Notation for Nonlinear First-Order Partial Differential Equations

Notation1

A nonlinear first-order partial differential equation is denoted as follows.

F(Du,u,x)=F(p,z,x)=0 \begin{equation} F(Du, u, x) = F(p, z, x) = 0 \label{eq1} \end{equation}

  • ΩRn\Omega \subset \mathbb{R}^{n} is an open set
  • xΩx\in \Omega
  • F:Rn×Rn×ΩˉRF : \mathbb{R}^n \times \mathbb{R}^n \times \bar{ \Omega } \to \mathbb{R} is the given function
  • u:ΩˉRu : \bar{ \Omega } \to \mathbb{R} is the variable of FF

Description

Solving a nonlinear first-order partial differential equation FF means finding a variable uu that satisfies F=0F=0 for the given FF. Here, let xx be a variable that encompasses both time and space.

x=(x1,,xn=t) x=(x_{1}, \dots, x_{n}=t)

The function FF is denoted as follows.

F=F(p,z,x)=F(p1,,pn,z,x1,,xn) F=F(p, z, x)=F(p_{1}, \dots, p_{n}, z, x_{1}, \cdots, x_{n})

  • p=Du(x)Rnp=Du(x) \in\mathbb{R}^n
  • z=u(x)Rz=u(x)\in \mathbb{R}
  • xΩˉx\in \bar{ \Omega }

And the function FF is assumed to be sufficiently smooth to be differentiable. This is generally the case, so it’s not particularly a strong condition. Then, the gradient of FF with respect to each variable is as follows.

{DpF=(Fp1, , Fpn)DzF=FzDxF=(Fx1, , Fxn) \begin{cases} D_{p} F=(F_{p_{1}},\ \cdots,\ F_{p_{n}}) \\ D_{z}F=Fz \\ D_{x}F=(F_{x_{1}},\ \cdots,\ F_{x_{n}} )\end{cases}

The Clairaut’s equation is represented using this notation as follows.

F(Du, u, x)=xDu+f(Du) F(Du,\ u,\ x)=xDu+f(Du)

Boundary Value Problem

Differential equations (eq1)\eqref{eq1} are commonly given along with boundary conditions. In such cases, they are denoted as follows.

F(Du, u, x)=0in Ωu=gon Γ \begin{align*} F(Du,\ u,\ x)&=0 && \text{in } \mathbb{\Omega} \\ u&=g && \text{on } \Gamma \end{align*} In this case, ΓΩ,g:ΓR\Gamma \subset \partial \Omega, g : \Gamma \to \mathbb{R}.


  1. Lawrence C. Evans, Partial Differential Equations (2nd Edition, 2010), p91-92 ↩︎