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Proof that Sine Squared Plus Cosine Squared Equals 1 📂Functions

Proof that Sine Squared Plus Cosine Squared Equals 1

Formulas

sin2θ+cos2θ=1 \sin^2\theta+\cos^2\theta=1

Proof

1-Addition Formula for Cosine

Using the Addition Theorem for Cosine, we can understand it very easily.

cos(θ1θ2)=cosθ1cosθ2+sinθ1sinθ2 \cos(\theta_{1}-\theta_2)=\cos\theta_{1}\cos\theta_2 + \sin\theta_{1}\sin\theta_2

Here, if we substitute θ\theta instead of θ1\theta_{1}, θ2\theta_2

cos(θθ)=cos2θ+sin2θ\cos(\theta-\theta)=\cos^2\theta + \sin^2\theta

    cos(θθ)=cos0=1\implies \cos(\theta-\theta)=\cos 0=1

    sin2θ+cos2θ=1\implies \sin^2\theta+\cos^2\theta=1

2-Pythagorean Theorem

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There is a unit circle with a radius of 1. Let’s look at the triangle formed by the unit circle’s radius, the perpendicular dropped to the xx axis from the point of tangency on the circle, and the xx axis itself. The length of the base is cosθ\cos\theta, the length of the height is sinθ\sin\theta, and the length of the hypotenuse is 11. Therefore, by the Pythagorean Theorem

sin2θ+cos2θ=1 \sin^2\theta+\cos^2\theta=1