Properties of Full Rank Matrices
Theorem1
Let’s refer to as matrix . Then, the necessary and sufficient condition for to have a full rank is for to be an invertible matrix.
Proof
Assume that has a full rank. Since is a square matrix , showing that the linear system only has the trivial solution, according to the equivocal condition of being an invertible matrix, suffices. Let be any solution. Then, belongs to the null space of . Moreover, belongs to the column space of . However, these two are orthogonal complements to each other.
Property of Orthogonal Complements
Therefore, holds. But since we assumed that has a full rank, the only that satisfies this is the trivial solution. Hence, is invertible.
Assume that is invertible. Then, the following linear system only has the trivial solution.
Then, holds, and this linear system also can only have the trivial solution. Therefore, by the equivalence condition, has a full rank.
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Howard Anton, Elementary Linear Algebra: Aplications Version (12th Edition, 2019), p422 ↩︎