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Chi-Square Distribution's Sufficient Statistics 📂Probability Distribution

Chi-Square Distribution's Sufficient Statistics

Theorem

Let’s assume we have a random sample X:=(X1,,Xn)χ2(r)\mathbf{X} := \left( X_{1} , \cdots , X_{n} \right) \sim \chi^{2} (r) that follows a chi-squared distribution. The sufficient statistic TT for rr is as follows. T=(iXi) T = \left( \prod_{i} X_{i} \right)

Proof

Relationship between gamma distribution and chi-squared distribution: Γ(r2,2)    χ2(r) \Gamma \left( { r \over 2 } , 2 \right) \iff \chi ^2 (r)

Sufficient statistic for the gamma distribution: Let’s say we have a random sample X:=(X1,,Xn)Γ(k,θ)\mathbf{X} := \left( X_{1} , \cdots , X_{n} \right) \sim \Gamma \left( k, \theta \right) that follows a gamma distribution.

The sufficient statistic TT for (k,θ)\left( k, \theta \right) is as follows.

T=(iXi,iXi) T = \left( \prod_{i} X_{i}, \sum_{i} X_{i} \right)

Chi-squared distribution is essentially a gamma distribution, and since the sufficient statistic for k=r/2k = r/2 in the gamma distribution is iXi\prod_{i} X_{i}, the sufficient statistic for the chi-squared distribution is also iXi\prod_{i} X_{i}.